Algebra · Step-by-step guide

Factoring Trinomials

Factor quadratic trinomials when the leading coefficient is 1 or another integer, with reliable checking steps.

By Tyler Blovat··9 min read
The short answer

Start with the central idea

To factor x2+bx+c\displaystyle x^2+bx+c, find two numbers whose product is c and sum is b. For ax2+bx+c\displaystyle ax^2+bx+c, use the ac method: split the middle term using numbers with product ac and sum b, then factor by grouping.

01

How it works

Build the method from meaning before memorizing the moves.

These are the decisions that make the procedure reliable. Read them once, then look for each idea in the worked examples below.

1

Take out the GCF first

A greatest common factor belongs outside the parentheses and makes the remaining trinomial simpler.

2

Use product and sum

The factor constants multiply to the final term while their cross-products combine to the middle term.

3

Check by multiplying

FOIL or distribute the factors. The original three terms should reappear exactly.

02

See the structure

A picture makes the relationships easier to remember.

−22vertex (0, −1)
The coordinate graph marks the vertex and the two x-intercepts of a representative quadratic.
03

Worked examples

Follow the reason for each line, then try to reproduce it without looking.

Example 1Leading coefficient 1

Factor x2+7x+12\displaystyle x^2+7x+12.

  1. Find numbers with product 12 and sum 7.
  2. The numbers are 3 and 4.
  3. Write the corresponding binomials.
Answer(x+3)(x+4)\displaystyle (x+3)(x+4)
Example 2Negative constant

Factor x2x12\displaystyle x^2-x-12.

  1. The product is −12 and sum is −1.
  2. Use −4 and 3.
  3. Check the middle terms: 3x4x=x\displaystyle 3x-4x=-x.
Answer(x4)(x+3)\displaystyle (x-4)(x+3)
Example 3ac method

Factor 6x2+11x+3\displaystyle 6x^2+11x+3.

  1. ac=18\displaystyle ac=18; use 9 and 2.
  2. Rewrite as 6x2+9x+2x+3\displaystyle 6x^2+9x+2x+3.
  3. Group: 3x(2x+3)+1(2x+3)\displaystyle 3x(2x+3)+1(2x+3).
Answer(3x+1)(2x+3)\displaystyle (3x+1)(2x+3)
04

Common mistakes—and how to avoid them

Accuracy improves fastest when you know what to check.

  • Skipping a common factor.

  • Using numbers with the right product but the wrong sum.

  • Failing to verify the result by multiplication.

05

Turn the explanation into a skill

Reading creates recognition. Independent practice creates recall.

Free printable worksheet · Answer key included

Factoring Trinomials

Practice monic trinomials, non-monic trinomials, and sign patterns.

Preview the worksheet

A strong practice loop: solve one example with the guide open, solve a similar problem without it, explain the method aloud, and return the next day for a short mixed review.

06

Practice problems with worked solutions

Solve each problem on paper, use the hint only if needed, then compare every step.

1

Factor x2+9x+20\displaystyle x^2+9x+20.

Show hint

Find factors of 20 that add to 9.

Show worked solution
  1. The numbers are 4 and 5.
  2. Write one binomial for each.
  3. Check: 4x+5x=9x\displaystyle 4x+5x=9x.

Answer: (x+4)(x+5)\displaystyle (x+4)(x+5)

2

Factor x22x15\displaystyle x^2-2x-15.

Show hint

Find numbers with product −15 and sum −2.

Show worked solution
  1. Use −5 and 3.
  2. Write (x5)(x+3)\displaystyle (x-5)(x+3).
  3. The cross terms combine to 2x\displaystyle -2x.

Answer: (x5)(x+3)\displaystyle (x-5)(x+3)

3

Factor 2x2+7x+3\displaystyle 2x^2+7x+3.

Show hint

Use the ac method.

Show worked solution
  1. ac=6\displaystyle ac=6; use 6 and 1.
  2. 2x2+6x+x+3\displaystyle 2x^2+6x+x+3.
  3. Group to get 2x(x+3)+1(x+3)\displaystyle 2x(x+3)+1(x+3).

Answer: (2x+1)(x+3)\displaystyle (2x+1)(x+3)

4

Factor 6x215x\displaystyle 6x^2-15x.

Show hint

Take out the GCF.

Show worked solution
  1. The GCF is 3x\displaystyle 3x.
  2. Divide both terms by 3x\displaystyle 3x.
  3. 6x215x=3x(2x5)\displaystyle 6x^2-15x=3x(2x-5).

Answer: 3x(2x5)\displaystyle 3x(2x-5)

5

Factor 3x210x8\displaystyle 3x^2-10x-8.

Show hint

Use numbers with product −24 and sum −10.

Show worked solution
  1. Use −12 and 2.
  2. 3x212x+2x8\displaystyle 3x^2-12x+2x-8.
  3. Group: 3x(x4)+2(x4)\displaystyle 3x(x-4)+2(x-4).

Answer: (3x+2)(x4)\displaystyle (3x+2)(x-4)

07

Frequently asked questions

Quick answers before you move on.

What should I remember first?

To factor x2+bx+c\displaystyle x^2+bx+c, find two numbers whose product is c and sum is b. For ax2+bx+c\displaystyle ax^2+bx+c, use the ac method: split the middle term using numbers with product ac and sum b, then factor by grouping.

How do I know whether I understand this topic?

You should be able to name the method, explain why each step is valid, complete a new example without copying, and check whether your answer is reasonable.

What should I do if I keep making the same mistake?

Write the error as a specific checkpoint—for example, “I will identify the hypotenuse before substituting.” Then use that checkpoint on three short problems rather than repeating a full page without feedback.